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Tricky Questions Percentage

Percentage - Aptitude

21.The salary of a person was reduced by 10%. By what percent should his reduced salary be raised so as to bring it at par with his original salary?

A. 86/9%

B. 95/9%

C. 111/9%

D. 100/9%

x

 

Option: D

Explanation

Consider the original salary be Rs.100

if the salary was reduced by 10%, his new salary will be Rs.90

Increase on 90 = 10%

so, increase on 100 = ((10/90) * 100)% = 100/9%)

Ans = 100/9%

Answer


22.When the price of the product was decreased by 10%, the number sold increased by 30%. What was the effect on the total revenue?

A. 17%

B. 19%

C. 23%

D. 31%

x

 

Option: A

Explanation

Consider the price of the product be Rs.100

consider the original sale be 100 pieces

then, total revenue = Rs.(100 * 100) = Rs.10000

if the price of product was decreased by 10% and number of pieces be increased by 30%

then, new total revenue = Rs.(90 * 130) = Rs.11700

increase in revenue = ((11700/10000) * 100)% = 17%

Ans = 17%

Answer


23.During one year, the population of a town increased by 5% and during the next year,the population decreased by 50%. If the total population is 9975 at the end of the second year, then what was the population size in the beginning of the first year?

A. 9000

B. 10000

C. 15000

D. 12000

x

 

Option: B

Explanation

In one year the population is increased by 5%

In next year the population is decreased by 5%

at the end of second year the population is 9975

then the population in the beginning of the first year is given by,

9975/[(1 + (5/100)) * (1 - (5/100))]

(9975 * (20/21) * (20/19)) = 10000

Ans = 10000

Answer


24.How many kg of pure salt must be added to 30 kg of 2% solution of salt and water to increase it to a 10% solution?

A. 7/3

B. 5/3

C. 8/3

D. 10/3

x

 

Option: C

Explanation

amount of salt in 30 kg solution = (2/100) * 30kg = 0.6kg

consider x kg of pure salt be added

then, (0.6 + x)/(30 + x) = 10/100

60 + 100x = 300 + 10x

90x = 240

x = 8/3

Ans = 8/3

Answer


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