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Permutation and Combination Questions
Permutation and Combination - Aptitude
1.Find the value of 60P3
x
Option: D
Explanation
60P3 = 60!/(60 - 3)!= 60!/57! = (60 * 59 * 58 * 57!)/57! = 60 * 59 * 58 = 205320
2.Find the value of 10C3
x
Option: A
Explanation
10C3 = (10 * 9 * 8)/(3 * 2 * 1) = 120
3.How many words can be formed by using all letters of the word 'BIHAR'?
x
Option: D
Explanation
BIHAR contains 5 different letters
Required number of words = 5P5 = 5! = 5 * 4 * 3 * 2 * 1 = 120
4.How many letters can be formed from the letters of the word 'DIRECTOR' so that the vowels are always together?
x
Option: A
Explanation
in the given word, treat the vowels IEO as one letter
thus, we have DRCTR (IEO)
this word has 6 letters of which R occurs 2 times and others are different
number of ways of arranging these letters = 6!/2! = 360
now 3 vowels can be arranged among themselves in 3! = 6 ways
required number of ways = (360 * 6) = 2160
5.In how many ways can a cricket eleven be chosen out of a batch of 15 players?
x
Option: A
Explanation
required number of ways = 15C11=15C15 - 11 = 15C4
=(15 * 14 * 13 * 12)/(4 * 3 * 2 * 1) = 1365
Related to Problems on Permutation and Combination
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