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Count Alphabets in a String
The following C program is full of fun. Let us assume your friend will type any odd names in your c console, your console should response by representing how many time every individual alphabetic characters are used by your friend.
C Program - Count Alphabets in a String
Lets write a C program to count every individual alphabetic characters used by your friend.
c-count-alphabets.c
#include <stdio.h>
#include <ctype.h>
#include <string.h>
int main()
{
int i, j, k = 0, c = 0, len, count[26];
char string[30];
printf("Enter a string : ");
gets(string);
len = strlen(string);
for(i = 0; i < 26; i++)
count[i] = 0;
for(i = 65; i < 90; i++)
{
for(j = 0; j < len; j++)
{
if(string[j] == toupper(i) || string[j] == tolower(i))
count[k] = ++c;
}
k++;
c=0;
}
printf("\n");
for(i = 65; i < 90; i++)
printf("%c ",i);
printf("\n");
for(i = 0; i < 25; i++)
printf("%d ",count[i]);
return 0;
}
Enter a string : TwoBracesIndia A B C D E F G H I J K L M N O P Q R S T U V W X Y Z 2 1 1 1 1 0 0 0 2 0 0 0 0 1 1 0 0 1 1 1 0 0 1 0 0 0
Note:
Here we iterate 26(Alphabetic count) times over each characters in the odd name entered by the user to find how many times each individual alphabetic characters are present.
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